Summary. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. High spin complexes are coordination complexes containing unpaired electrons at high energy levels. Which of the following is a high spin complex ? The difference in energy between high and low spin is dependent upon the ligand mix and coordination stereochemistry. Ligands that produce small Δ leads to a high-spin complex and are said to be weak field ligands. A high spin energy splitting of a compound occurs when the energy required to pair two electrons is greater than the energy required to place an electron in a high energy state. (b) [Co(en) 3] 3+ is more stable than [CoF 6] 3−. Solution for Which of the following statements about Fe(CO)5 is correct ? The complex [FeF6]4– is para magnetic and uses outer orbital (4d) in hybridisation (sp3d2) ; it is thus called as outer orbital or high spin or spin free complex. High-spin and low-spin systems The first d electron count (special version of electron configuration ) with the possibility of holding a high spin or low spin state is octahedral d 4 since it has more than the 3 electrons to fill the non-bonding d orbitals according to ligand field theory or the stabilized d orbitals according to crystal field splitting. A. Cr2+ B. Mn4+ C. Fe3+ D. Co3+ E. Ni2+ 17. Coordination Compounds Multiple Choice Questions and Answers for competitive exams. Which of the following high-spin complexes has the greatest number of unpaired electrons? Angewandte Chemie International Edition 2012 , 51 (40) , 10045-10049. Co exists as Co3+ in [CoF6]3–. Atomic number of Mn, Fe and Co are 25,26 and 27 respectively. The unpaired electrons can be calculated as en is a strong field ligand, therefore, pairing of electrons will take place. The unpaired electrons in the d-orbitals do not tent to pair up because F, CuSO4 reacts with an excess of hypo solution to produce a CuI complex of, The co-ordination number of copper in the complex formed by adding excess of NH3 to CuSO4 solution is. Please explain. (2) [Co(NH) * [CO(NH3)j? Which of the following metal ions could be found in both high-spin and low-spin configurations in octahedral complex ions? a) Fe(3+) 5 3d electrons. With the ligand system 4'-(4'''-benzo-[15]-crown-5)-methyloxy-2,2':6',2''-terpyridine ([b15c5]-tpy) iron(II) and cobalt(II) complexes of the type [M([b15c5]-tpy)2]2+ have been created.rnAll synthesized iron(II) complexes are in a diamagnetic low spin state in the temperature range 300 – 400 K due to the high ligand field strength of the terpyridine. The energy differences between the t2g and eg orbitals determines whether an octahedral complex is high or low spin. LEARNING APP ANSWR CODR XPLOR SCHOOL OS … For biological ligands, H2O and NH3, the most stable spin state is high spin (S = 3/2). $$ [Ni(NH_3)_6]^{2+}$$ Note: In the following questions two or more options may be correct. is a strong field ligand which pairs the all unpaired electrons of which results no unpaired electron in the and it form low spin complex. Which of the following ions could exist in either the high-spin or low-spin state in an octahedral complex? Which of the following ligands is most likely to form a high spin octahedral complex with cobalt(II)? From this experiment, the measured magnetic moment of low-spin d 6 [Fe(CN) 6] 4− ion confirms that iron is diamagnetic, whereas the high-spin d 6 [Fe(H 2 O) 6] 2+ complex has four unpaired electrons with a magnetic moment CN-If M represents a transition element, which of the following oxides should be the least basic? The high-spin octahedral complex has a total spin state of #+2# (all unpaired #d# electrons), while a low spin octahedral complex has a total spin state of #+1# (one set of paired #d# electrons, two unpaired). For the octahedral complexes of F e 3 + in S C N − (thiocyanato-S) and in C N − ligand environments, the difference between the spin-only magnetic moments in Bohr magnetons (when approximated to the nearest integer) is: High spin optimized geometries for these model compounds give structures close to octahedral symmetry. The geometry is prevalent for transition metal complexes with d 8 configuration. Which of the following ions could exist in only the high-spin state in an octahedral complex? (2) B) Add All Symmetry Labels. d) paramagnetic, with 5 unpaired electrons. 22 - How many unpaired electrons are expected for... Ch. c) paramagnetic, with 4 unpaired electrons. Determine the following: (a) (6 pts.) Which of the following species is diamagnetic? The crystal field energy-level diagram. Select one: a. Which of the following is a high spin (spin-free) complex ? Thanks! The Cl-complex will be in a high spin state with 4 unpaired electrons. The Carboxylate Twist: Hysteretic Bistability of a High-Spin Diiron(II) Complex Identified by Mössbauer Spectroscopy. (d) [CoF 6] 3− forms high spin complex. In this screencast, Andrew Burrows walks you through the use of magnetic data to determine whether a complex is high spin or low spin. Which of the following is a low spin (spin-paired) complex? Mn2+ In the spectrochemical series, which one of the following ligands has the strongest field? (a) \left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right… This suggests that the net will give a low-spin complex. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. 22 - Excess silver nitrate is added to a solution... Ch. K3CoF6 is a high spin complex. Is the complex paramagnetic or diamagnetic? This complex is a) paramagnetic, with 1 unpaired electron. Which of the following is a high-spin (spin-free) complex? Which of the following is a high-spin (spin-free) complex? Start Your Numerade Subscription for 50% Off!Join Today. MO3. Determine the following: (a) (6 pts.) Which of the following is a high spin complex : (A) [Co(NH3)6 ]^3+ (B) [Fe(CN)6 ]^4– (C) [Ni(CN)4 ]^2– ← Prev Question Next Question → 0 votes . answered Apr 24, 2018 by santoshjha (143k points) selected Apr 27, 2018 by Vikash Kumar . CrF 6 4-is known to be a high-spin complex. are solved by group of students and teacher of JEE, which is also the … This is true because of the nature of the t2g and eg orbitals orbitals. a) Co^2+ b)Mn^3+ c)Cr^2+ d)Fe^3+ e) Cr^3+ Which one of the following ions cannot form both a high spin and low spin octahedral complex ion? Which of the following is a low - spin (spin - paired) complex? 22 - Which of the following high spin complexes has the... Ch. 1 Answer +1 vote . Explain Your Choice. Usually, octahedral and tetrahedral coordination complexes ar… All metal ions you have listed CANNOT form both high and low spin octahedral complexes. I think it's D, but I'm not sure. (iii) CO is a stronger ligand than NH 3 for many metals. Free PDF Download of CBSE Chemistry Multiple Choice Questions for Class 12 with Answers Chapter 9 Coordination Compounds. The configuration of, The unpaired electrons in the d-orbitals do not tent to pair up because F– is weak ligand. Best answer. It is paramagnetic and high spin complex b. The crystal field splitting energy, , A. is larger for tetrahedral complexes than for Mn2+ In the spectrochemical series, which one of the following ligands has the strongest field? (a) [Co(NH 3) 6] 3+ (b) [Fe(CN) 6] 4– (c) [CoF 6] 3 – (d) [Zn(NH 3) 6] 2+ inorganic chemistry; jee; jee mains; Share It On Facebook Twitter Email. Hence, there are no unpaired electrons . CrF 6 4-is known to be a high-spin complex. Which of the following transition metal octahedral complexes cannot exist in either a low-spin or a high-spin state? So : sp3d2 hybrid orbitals Six pairs of electrons from six F– ions. Circle one (c) (2 pts.) Cu^2+ is d^10, meaning it has 10 electrons in its 5 d-orbitals.
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